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TOPIC: Show/hide a field based on true/false validation ?

Show/hide a field based on true/false validation ? 6 years 6 months ago #37435

  • Paladin
  • Paladin's Avatar
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  • Posts: 6
Hello to RSForm Pro Community and Support !

We all know RSFormPro has the Conditional Fields feature.
But there are no a condition there what allows to show or hide a field basing on Validation rule for another field.

AT-FIRST, as example, let's assume we set a custom valudation rule in
components/com_rsform/helpers/customvalidation.php
as explained in www.rsjoomla.com/support/documentation/r...alidation-rules.html
  public static function validationTest($value, $extra = null, $data = null)
  {
    // The following makes sure the submitted value is "test"
    if ($value == 'test')
    {
      // Return true if the validation passed.
      return true;
    }
    else
    {
      // Return false if the validation didn't pass.
      return false;
    }
  }
NEXT - we create a usual textfield with name 'texttest1' and set validation 'required' for the custom function 'validationTest' as above.
NEXT - we create a free text with name "freetest2" - without any validation, but hidden by default.

The question - is it possible (using a Javascript or PHP code in Form Properties) to show 'freetest2' for frontend user - only IF validation is FALSE ?
Saying simple - if you enter something wrong in 'texttest1' field - it says about an invalid input as always - but ALSO RSForm opens 'freetest2' field.

Actually this is very similar to Conditional Fields feature, but as said before - current Conditional Fields feature does not allow show/hide RSForm fields basing on true/false result of a validation rule for another field.

So that, thanks in advance for any code examples to try !
Best regards,
Serge
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